WGU Foundations of Programming (Python) - E010 JIV1 : Foundations-of-Programming-Python

Exam Code: Foundations-of-Programming-Python
Exam Name: Foundations of Programming (Python) - E010 JIV1
Updated: Sep 16, 2026
Q & A: 62 Questions and Answers

About WGU Foundations-of-Programming-Python Exam Questions

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WGU Foundations-of-Programming-Python Exam Syllabus Topics:

Section	Objectives
Introduction to Object-Oriented Programming	- Basic OOP concepts - Classes and objects
Control Flow	- Loops (for, while) - Conditional statements (if / elif / else)
File Handling and Exceptions	- Exception handling (try/except) - Reading and writing files
Python Programming Fundamentals	- Variables and data types - Syntax and basic structure - Operators and expressions
Debugging and Testing Basics	- Error identification and correction - Basic testing concepts
Functions and Modularity	- Modules and imports - Function definition and scope
Data Structures	- Basic data manipulation - Lists, tuples, dictionaries

WGU Foundations of Programming (Python) - E010 JIV1 Sample Questions:

Question #1

Write a complete function password_strength(password) that returns " Strong " if the password is at least 8 characters long and contains both letters and numbers, " Weak " otherwise.
For example, password_strength( " abc123def " ) should return " Strong " .
def password_strength(password):
# TODO: Return " Strong " or " Weak " based on password criteria
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
# TODO: Add your return logic here based on has_letter and has_number
pass

Reveal Solution Discussion 0

Correct Answer:

See the Step by Step Solution below in Explanation.
Explanation:
Step 1: First, check the password length using len(password).
Step 2: If the password has fewer than 8 characters, return " Weak " immediately.
Step 3: Create two Boolean variables: has_letter and has_number.
Step 4: Loop through each character in the password.
Step 5: Use .isalpha() to check for letters and .isdigit() to check for numbers.
Step 6: If the password contains both at least one letter and at least one number, return " Strong " .
Step 7: Otherwise, return " Weak " .
Correct code:
def password_strength(password):
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
if has_letter and has_number:
return " Strong "
else:
return " Weak "
Example:
print(password_strength( " abc123def " ))
print(password_strength( " abcdefgh " ))
print(password_strength( " 12345678 " ))
Output:
Strong
Weak
Weak

Question #2

What happens when theRunbutton is clicked in a Python development environment?

A. The file is saved without being executed.
B. The currently open Python script is executed.
C. The code is converted to a different programming language.
D. A file browser window opens.

Reveal Solution Discussion 0

Correct Answer: B 🗳️

Explanation: Only visible for BraindumpsPrep members. You can sign-up / login (it's free).

Question #3

A program needs to display only positive, non-zero numbers from a list containing a mixture of integer and decimal values. Which conditional statement should be placed inside the loop?

A. if number < 0:
B. if number != 0:
C. if number > = 1:
D. if number > 0:

Reveal Solution Discussion 0

Correct Answer: D 🗳️

Explanation: Only visible for BraindumpsPrep members. You can sign-up / login (it's free).

Question #4

Fix the missing return statement in this function that should return whether a number is even.
def is_even(number):
if number % 2 == 0:
True
else:
False

Reveal Solution Discussion 0

Correct Answer:

See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The expression number % 2 == 0 checks whether the number is even.
Step 2: The original code writes True and False, but it does not return them.
Step 3: A function must use the return statement to send a value back to the caller.
Correct code:
def is_even(number):
if number % 2 == 0:
return True
else:
return False
Simplified correct code:
def is_even(number):
return number % 2 == 0
Example:
print(is_even(4))
print(is_even(7))
Output:
True
False

Question #5

Which Python data structure contains only unique elements and does not support indexing?

A. Tuple
B. Set
C. List
D. Dictionary

Reveal Solution Discussion 0

Correct Answer: B 🗳️

Explanation: Only visible for BraindumpsPrep members. You can sign-up / login (it's free).

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